By Margaret L. Lial, John Hornsby, Terry McGinnis

ISBN-10: 0321168305

ISBN-13: 9780321168306

The Lial sequence has helped millions of scholars reach developmental arithmetic via its pleasant writing kind, a variety of reasonable examples, vast challenge units, and whole supplementations package deal. in accordance with its confirmed music list, this revision features a new open layout, extra routines and functions, and extra positive aspects to assist either scholars and teachers be triumphant.

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**Extra info for Algebra for College Students**

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Photo not available An Addison-Wesley product. Copyright © 2004 Pearson Education, Inc. 58 CHAPTER 2 Linear Equations, Inequalities, and Applications The steps used in the following examples are very similar to those used in solving linear equations. When you are solving for a specified variable, the key is to treat that variable as if it were the only one; treat all other variables like numbers (constants). The following additional suggestions may be helpful. Solving for a Specified Variable Step 1 Get all terms containing the specified variable on one side of the equation and all terms without that variable on the other side.

C) Ϫ͑m Ϫ 5n͒ Ϫ1͑m Ϫ 5n͒ Ϫ1͑m͒ ϩ ͑Ϫ1͒͑Ϫ5n͒ Ϫm ϩ 5n Identity property Distributive property Multiply. Now Try Exercises 21 and 23. Expressions such as 12m and 5n from Example 2 are examples of terms. A term is a number or the product of a number and one or more variables. Terms with exactly the same variables raised to exactly the same powers are called like terms. Some examples of like terms are 5p and Ϫ21p Ϫ6x 2 and 9x 2. Like terms Some examples of unlike terms are 3m and 16x 7y 3 and Ϫ3y 2.

OBJECTIVES 1 Use the distributive property. 2 Use the inverse properties. 3 Use the identity properties. OBJECTIVE 1 Use the distributive property. 4 Use the commutative and associative properties. Notice that 2͑3 ϩ 5͒ 2 и 8 16 and 5 Use the multiplication property of 0. 2 и 3 ϩ 2 и 5 6 ϩ 10 16, so 3 2͑3 ϩ 5͒ 2 и 3 ϩ 2 и 5. 5 2 2 Area of left part is 2 . 3 = 6. Area of right part is 2 . 5 = 10. Area of total rectangle is 2(3 + 5) = 16. FIGURE 16 This idea is illustrated by the divided rectangle in Figure 16.

### Algebra for College Students by Margaret L. Lial, John Hornsby, Terry McGinnis

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